Online C_ABAPD_2309 Tests - C_ABAPD_2309 Reliable Test Dumps

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These SAP C_ABAPD_2309 practice tests simulate the real SAP Certified Associate - Back-End Developer - ABAP Cloud (C_ABAPD_2309) exam pattern, track your progress, and help you overcome mistakes. Our SAP Certified Associate - Back-End Developer - ABAP Cloud (C_ABAPD_2309) desktop software is compatible with Windows. Whereas, the web-based SAP C_ABAPD_2309 Practice Exam works online on iOS, Linux, Android, Windows, and Mac. Additionally, the web-based SAP Certified Associate - Back-End Developer - ABAP Cloud (C_ABAPD_2309) practice exam is also compatible with MS Edge, Internet Explorer, Opera, Firefox, Safari, and Chrome.

SAP C_ABAPD_2309 Exam Syllabus Topics:

Topic	Details
Topic 1	ABAP SQL and code pushdown: It discusses ABAP SQL, arithmetic expressions, manage dates, and create joins.
Topic 2	ABAP core data services and data modeling: It focuses on Core Data Services (CDS) views, SAP HANA database tables, foreign key relationships, and annotations.
Topic 3	ABAP RESTful Application Programming Model: This topic explains the ABAP Restful Application Programming model, ABAP development, and the architecture of the ABAP Restful Application Programming model.
Topic 4	Object-oriented design: It measures your knowledge about encapsulation, upcast, inheritance, polymorphism, and interfaces. Moreover, the topic evaluates your knowledge about constructor calls, Exception classes, and singleton pattern.

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SAP Certified Associate - Back-End Developer - ABAP Cloud Sample Questions (Q30-Q35):

NEW QUESTION # 30
What is the sequence priority when evaluating a logical expression?
A) NOT 1
B) OR 3
C) AND 2

A. CAB
B. A B C
C. B A C
D. A C B

Answer: D

Explanation:
The sequence priority when evaluating a logical expression is C. A C B, which means NOT, AND, OR. This is the order of precedence of the Boolean operators in ABAP, which determines how the system implicitly parenthesizes all logical expressions that are not closed by explicit parentheses. The operator with the highest priority is evaluated first, and the operator with the lowest priority is evaluated last. The order of precedence of the Boolean operators in ABAP is as follows12:
NOT: The NOT operator is a unary operator that negates the logical expression that follows it. It has the highest priority and is evaluated before any other operator. For example, in the expression NOT a AND b, the NOT operator is applied to a first, and then the AND operator is applied to the result and b.
AND: The AND operator is a binary operator that returns true if both logical expressions on its left and right are true, and false otherwise. It has the second highest priority and is evaluated before the OR and EQUIV operators. For example, in the expression a AND b OR c, the AND operator is applied to a and b first, and then the OR operator is applied to the result and c.
OR: The OR operator is a binary operator that returns true if either or both logical expressions on its left and right are true, and false otherwise. It has the third highest priority and is evaluated after the NOT and AND operators, but before the EQUIV operator. For example, in the expression a OR b EQUIV c, the OR operator is applied to a and b first, and then the EQUIV operator is applied to the result and c.
EQUIV: The EQUIV operator is a binary operator that returns true if both logical expressions on its left and right have the same truth value, and false otherwise. It has the lowest priority and is evaluated after all other operators. For example, in the expression a AND b EQUIV c OR d, the EQUIV operator is applied to a AND b and c last, after the AND and OR operators are applied.

NEW QUESTION # 31
What would be the correct expression to change a given string value 'mr joe doe' into 'JOE' in an ABAP SQL field list?

A. SELECT FROM TABLE dbtabl FIELDS
Of1,
substring(upper('mr joe doe'), 4, 3) AS f2_sub_up, f3,...
B. SELECT FROM TABLE dbtabl FIELDS
Of1,
substring(lower(upper( 'mr joe doe' ) ), 4, 3) AS f2_sub_lo_up, f3,
C. SELECT FROM TABLE dbtabl FIELDS
Of1,
upper(left( 'mr joe doe', 6)) AS f2_up_left, f3,
D. SELECT FROM TABLE dbtabl FIELDS
Of1,
left(lower(substring( 'mr joe doe', 4, 3)), 3) AS f2_left_lo_sub, f3,

Answer: A

Explanation:
The correct expression to change a given string value 'mr joe doe' into 'JOE' in an ABAP SQL field list is C. SELECT FROM TABLE dbtabl FIELDS Of1, substring(upper('mr joe doe'), 4, 3) AS f2_sub_up, f3,... This expression uses the following SQL functions for strings12:
upper: This function converts all lowercase characters in a string to uppercase. For example, upper('mr joe doe') returns 'MR JOE DOE'.
substring: This function returns a substring of a given string starting from a specified position and with a specified length. For example, substring('MR JOE DOE', 4, 3) returns 'JOE'.
AS: This keyword assigns an alias or a temporary name to a field or an expression in the field list. For example, AS f2_sub_up assigns the name f2_sub_up to the expression substring(upper('mr joe doe'), 4, 3).
You cannot do any of the following:
A) SELECT FROM TABLE dbtabl FIELDS Of1, upper(left( 'mr joe doe', 6)) AS f2_up_left, f3,...: This expression uses the wrong SQL function for strings to get the desired result. The left function returns the leftmost characters of a string with a specified length, ignoring the trailing blanks. For example, left( 'mr joe doe', 6) returns 'mr joe'. Applying the upper function to this result returns 'MR JOE', which is not the same as 'JOE'.
B) SELECT FROM TABLE dbtabl FIELDS Of1, left(lower(substring( 'mr joe doe', 4, 3)), 3) AS f2_left_lo_sub, f3,...: This expression uses unnecessary and incorrect SQL functions for strings to get the desired result. The lower function converts all uppercase characters in a string to lowercase. For example, lower(substring( 'mr joe doe', 4, 3)) returns 'joe'. Applying the left function to this result with the same length returns 'joe' again, which is not the same as 'JOE'.
D) SELECT FROM TABLE dbtabl FIELDS Of1, substring(lower(upper( 'mr joe doe' ) ), 4, 3) AS f2_sub_lo_up, f3,...: This expression uses unnecessary and incorrect SQL functions for strings to get the desired result. The lower function converts all uppercase characters in a string to lowercase, and the upper function converts all lowercase characters in a string to uppercase. Applying both functions to the same string cancels out the effect of each other and returns the original string. For example, lower(upper( 'mr joe doe' ) ) returns 'mr joe doe'. Applying the substring function to this result returns 'joe', which is not the same as 'JOE'.

NEW QUESTION # 32
What are some characteristics of secondary keys for internal tables? Note: There are 3 correct answers to this question.

A. Sorted secondary keys do NOT have to be unique.
B. Secondary keys must be chosen explicitly when you actually read from an internal table.
C. Multiple secondary keys are allowed for any kind of internal table.
D. Hashed secondary keys do NOT have to be unique.
E. Secondary keys can only be created for standard tables.

Answer: A,B,C

Explanation:
Secondary keys are additional keys that can be defined for internal tables to optimize the access to the table using fields that are not part of the primary key. Secondary keys can be either sorted or hashed, depending on the table type and the uniqueness of the key. Secondary keys have the following characteristics1:
* A. Secondary keys must be chosen explicitly when you actually read from an internal table. This means that when you use a READ TABLE or a LOOP AT statement to access an internal table, you have to specify the secondary key that you want to use with the USING KEY addition. For example, the following statement reads an internal table itab using a secondary key sec_key:
READ TABLE itab USING KEY sec_key INTO DATA(wa).
If you do not specify the secondary key, the system will use the primary key by default2.
* B. Multiple secondary keys are allowed for any kind of internal table. This means that you can define more than one secondary key for an internal table, regardless of the table type. For example, the following statement defines an internal table itab with two secondary keys sec_key_1 and sec_key_2:
DATA itab TYPE SORTED TABLE OF ty_itab WITH NON-UNIQUE KEY sec_key_1 COMPONENTS field1 field2 sec_key_2 COMPONENTS field3 field4.
You can then choose which secondary key to use when you access the internal table1.
* D. Sorted secondary keys do NOT have to be unique. This means that you can define a sorted secondary key for an internal table that allows duplicate values for the key fields. A sorted secondary key maintains a predefined sorting order for the internal table, which is defined by the key fields in the order in which they are specified. For example, the following statement defines a sorted secondary key sec_key for an internal table itab that sorts the table by field1 in ascending order and field2 in descending order:
DATA itab TYPE STANDARD TABLE OF ty_itab WITH NON-UNIQUE SORTED KEY sec_key COMPONENTS field1 ASCENDING field2 DESCENDING.
You can then access the internal table using the sorted secondary key with a binary search algorithm, which is faster than a linear search3.
The following are not characteristics of secondary keys for internal tables, because:
* C. Hashed secondary keys do NOT have to be unique. This is false because hashed secondary keys must be unique. This means that you can only define a hashed secondary key for an internal table that does not allow duplicate values for the key fields. A hashed secondary key does not have a predefined sorting order for the internal table, but uses a hash algorithm to store and access the table rows. For example, the following statement defines a hashed secondary key sec_key for an internal table itab that hashes the table by field1 and field2:
DATA itab TYPE STANDARD TABLE OF ty_itab WITH UNIQUE HASHED KEY sec_key COMPONENTS field1 field2.
You can then access the internal table using the hashed secondary key with a direct access algorithm, which is very fast.
* E. Secondary keys can only be created for standard tables. This is false because secondary keys can be created for any kind of internal table, such as standard tables, sorted tables, and hashed tables. However, the type of the secondary key depends on the type of the internal table. For example, a standard table can have sorted or hashed secondary keys, a sorted table can have sorted secondary keys, and a hashed table can have hashed secondary keys1.
References: 1: Secondary Table Key - ABAP Keyword Documentation 2: READ TABLE - ABAP Keyword Documentation 3: Sorted Tables - ABAP Keyword Documentation : Hashed Tables - ABAP Keyword Documentation

NEW QUESTION # 33
Which field is defined incorrectly?

A. field3
B. field2
C. field4
D. field1

Answer: C

Explanation:
The field4 is defined incorrectly in the ABAP code snippet. The reason is that the data type c (character) cannot have a decimal places specification. The decimal places specification is only valid for the data types p (packed number) and f (floating point number)1. Therefore, the field4 definition should either omit the decimal places specification or change the data type to p or f.

NEW QUESTION # 34
Exhibit

Which of the following ABAP SQL snippets are syntactically correct ways to provide a value for the parameter on line #4? Note: There are 2 correct answers to this question

A. ...SELECT * FROM demo_cds_param_view entity (p_date: $session.system_date)...
B. ...SELECT * FROM demo_cds_param_view_entity (p_date: 20238181')... )
C. ...SELECT * FROM deno_cds_param_view_entity (p_date = @
(cl_abap_context_info->get_system_date ())...
D. ...SELECT * FROM deno_cds_param_view_entity (p_date - '20230101')... )

Answer: C,D

NEW QUESTION # 35
......

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